# Java bitwise AND to check a given number is odd or even

Let’s learn java bitwise AND to check a given number is odd or even.

## Java bitwise AND to check a given number is odd or even

Basically to check if number is even we divide it by 2 and it’s remainder will be 0. Meanwhile for odd number remainder is 1 when divided by 2.

Bitwise AND (&) operator returns bit by bit AND of input values. Here we have to check if last bit is 1. If last bit is 1 then it is odd else it is even. Also integer numbers are represented as 2’s complement.

Also read – java string trim() method

For even number it has 0 as there Least Significant Bit (LSB). Let’s see how to check if number is even or odd without using modulus operator or remainder operator,

```/**
* java check if number is even
* java program to check if a number is even or odd without using modulus or * remainder operator.
*
* @author sachin
*/

public class EvenOddBitwise
{
static int checkEven(int num)
{
//  if we perform bitwise AND between 1 and "num" result will be 0
return(num & 1);
}```
```   public static void main(String[] args)
{
int number = 501;
if(checkEven(number) == 0)
{
System.out.print("Even number");
}
else
{
System.out.print("Odd number");
}
}
}

```

Output:

Odd number

Meanwhile we can also check if number is even or odd using division operator ( / ).

Here division operator basically returns quotient. For example, if we take a number and divide by two and multiply result with 2 then the number will be less in case of odd number and equal in case of even number.

```int result = number / 2;
if(result * 2 == number)
{
System.out.println("Even number");
}```