Java program to sort names in an alphabetical order

Let’s learn java program to sort names in an alphabetical order.

Java program to sort names in an alphabetical order

Now let’s see steps to sort names in an alphabetical order.

• In the below java program first user enters number of strings using nextInt() method Scanner class.
• In the next step number of strings is stored in integer variable ‘number’. Now create String array ‘names’.
• Then using for loop store all the strings entered by user. In if statement compareTo() method is used to compare first letter of each string to store in alphabetical order.
• Finally for loop is used to print names in alphabetical order.

Here’s program to sort names in an alphabetical order.

import java.util.Scanner;
public class SortNamesAlphabeticalOrder
{
   public static void main(String[] args)
   {
      int number;
      String str;
      Scanner sc1 = new Scanner(System.in);
      System.out.println("Please enter number of strings: ");
      number = sc1.nextInt();
      String[] names = new String[number];
      Scanner sc2 = new Scanner(System.in);
      System.out.println("Enter all strings: ");
      for(int a = 0; a < number; a++)
      {
         names[a] = sc2.nextLine();
      }
      for(int a = 0; a < number; a++)
      {
         for(int b = a + 1; b < number; b++)
         {
            // java alphabetical sort
            if(names[a].compareTo(names[b]) > 0)
            {
               str = names[a];
               names[a] = names[b];
               names[b] = str;
            }
         }
      }
      System.out.println("After sorting names in an alphabetical order: ");
      for(int a = 0; a < number - 1; a++)
      {
         System.out.println(names[a] + ", ");
      }
      System.out.print(names[number - 1]);
      sc1.close();
      sc2.close();
   }
}

Output: